clj

should be no2?? choose number that is less than the first one while greater than "leftover beans"/3. Which control wht no.3 & 4 &5 chooses& _( o3 `- g9 E0 {3 Z  r& E$ Y! p
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If no.1 takes very little bean.. e.g. 3 beans.. then no.2 just take one more than him.. bcos when the forth and fifth person is choosing, they should not be able to guess easily wht no.2 has chosen....if no.1 takes 3 beans.. (the logically minimum... since nobody will choose 1... and therefore 2 is the minmum that a normal person will choose... but since equilvalent is dead as well.. minimum will choose is 3).. then no.2 will take 4 beans.. no.3 should be able to tell that one person chose 3 & 4 beans and is highly likely to choose 4 too and hope that 4 &5 choose higher since it is harder to guess the highest and lowest when the numbers are so close together. Therefore no.2 should be the best position???