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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆, {% ~, U4 r) \( y* h
共四堆
  x9 B( W6 g/ m& ltvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重3 Q$ v4 s) h" b0 G: w" a
在异常的那一堆中在称一次3 s: `3 V  N* w. k- I, F2 v
就可以找到了
divde the 12 balls into 3 sets of 4.
7 |. D( J4 v, [8 I" hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
3 R8 ]1 `# X$ p: v) ~' G公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third
8 E: h- W* p, W3 i8 Hif one of the 2 is heavier, then the heavy one is in that set
/ s* {: _5 H4 M; Dthen divide the 4 balls into 2.公仔箱論壇/ d6 ?, b4 n& F1 M9 Q9 c# w* l
weigh them
3 l% _1 Z7 Z9 Jand divide the heavier into 1
% L  }( O- v; |8 b7 |+ Rtvb now,tvbnow,bttvband weight them.
6 g% F6 m8 D! }$ r7 s: _3 x weighing and get the ans.  : _- v* R/ A1 S0 F% X9 z* {  I
in less than 15 secs.
1. 6 aside and weight.
" v+ [. W% O! f: @2. heavier side from (1), 3 aside weight again.
9 [+ V! U; q" h5 A$ Y( c( BTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 8 d6 f  c4 e+ h

% N) ^$ U1 |1 P8 B/ T# C& ATVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
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