ericchan1

好難呀．．．

eleven20

難...

jeffreyhohoyuan

好難呀．．．．

百事可乐

ddd

dimsum199

好難喎

PokChop

There is 12 balls.. divide them into piles of 48 x- |0 k2 f- a" N8 {
so 3 groups for 4..name is A,B,Cwww.tvboxnow.com/ ]0 W- N" j* H- O! K- K% z  m
case 1: www.tvboxnow.com, v1 q! R- o! |4 K& E
measure A -- B
# `- p/ X' W) |7 KA or B is heavier 公仔箱論壇- n- @' L" M& X8 }; i. Z# `
divide that group into 2 by 2
7 v- i( P9 O0 w) Y9 {! Z# t公仔箱論壇then divide heavier group into 1 by 1
3 Y: G7 V$ \; B' {4 k/ u/ Q/ K9 u& X6 S; s4 F$ }0 V  {
case 2:+ B$ R, g( i; q6 m+ w# C, ]
A and B is the same.. therefore C has the heavier ball3 f! \% _# ~" ?. }
divide C into 2 by 2; x" K# L( j' e% \
then divide heavier group into 1 by 1..www.tvboxnow.com& P# O& _( j4 V3 q( K8 d# ~

& }, A  G; K( `/ j7 n6 ^tvb now,tvbnow,bttvbgot it in 30 seconds.. not so hard -.-'

curlihead

thx

curlihead

i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.$ I, c, x- B4 g( x
$ i& }1 Y8 J# H0 P  g, n  F
they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.

boringaya

睇下先

mm_penguin

do this is so boring...# v0 o7 ?( @) k, t
play game la~~~

306247000

[-X OK la^:)^ ^:)^

diy123

一知道有答案睇就唔想谂咁耐了

hey8hey8

?

magcsm

why?

jackytan3344

多謝大大的分享