That is a very simple mathematics question.
) }2 X; `+ ^4 Q* k, d; J; Xtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Childwww.tvboxnow.com* ^; E y* e9 ^# _+ P
6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& i# \- N$ g1 r* w7 b
x + y + z = 100 Formula 2
0 z# v9 {! o. J/ D% J# P) Y: kSimplify Formula 2 into z, we get z = 100 - x - y Formula 3+ ?# c: }: M& M2 \! J: G# N3 m
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 T, E7 e/ [, M# o3 K; M
Formula 4 can change into 11x + 5y = 100 Formula 5* e4 V7 U% ^- n
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.! t' m; a9 I( K& n8 G9 ^
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# a" M! M0 t y$ j3 E
Eventually, the answer is 20 female and 80 children and no male. |