That is a very simple mathematics question.
+ i) f5 v ^& }/ UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child公仔箱論壇- s0 o0 l6 o4 W' ~6 {3 [, w0 _
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb% ~8 ?; c; A9 c8 B
x + y + z = 100 Formula 2 H0 e, C" V$ ]! T9 @
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3) i: L. p8 n5 A6 n
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ v' q& F$ B5 _3 x0 Y+ pFormula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇/ @( \; I8 `6 v
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
3 a& R2 K# n+ a4 q+ ]" z- ltvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
# \) \; J, ?/ T) J4 ?+ PEventually, the answer is 20 female and 80 children and no male. |