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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
! m% [- \1 b! u* C; y, ywww.tvboxnow.com1st u divide the ball into two group (i group 6 ball)公仔箱論壇) m8 E3 R9 n& f0 Y
then 称 them c which side is the heavy
5 d) s& p  S3 f% v$ \! ]www.tvboxnow.comthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group www.tvboxnow.com% i) A# O5 @1 ?5 S! g! l; S% W; b
if not balance take the heavy and then
8 h+ V4 u& @: u# ftake the heavy group divided into 2 group i group contain 1 ball than 称 it
, ~5 i( K7 R. j( Lthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
7 i1 s) c) i! s* [( ^2 h" Z( m0 ^5 Z(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇; e" V  ?0 u/ {* V+ g0 y0 n# J& [
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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