hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
5 L9 A) I0 a: Q+ C" q; t* L/ {0 [1st u divide the ball into two group (i group 6 ball)0 k" e0 r* m0 m- t: C+ _0 d
then 称 them c which side is the heavy tvb now,tvbnow,bttvb6 [1 V/ r) _& r2 O
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
0 `" b! w' E' K/ ~. t公仔箱論壇if not balance take the heavy and then
; O. e; Z) h2 Q& C6 |5 t. kwww.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it 9 U1 Q! D! q. I/ H8 e
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇4 D- ^6 g! a, c/ Y5 R) Y" @( T
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边, i5 H( Q/ H" g0 i: l4 W8 S6 w
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me