hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^1 u, b6 K$ D3 z$ i$ k
1st u divide the ball into two group (i group 6 ball)公仔箱論壇4 X9 O# S. a" F( d2 y9 T* {
then 称 them c which side is the heavy ( ?* G: W2 ]! i; J5 B3 k8 e
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
' O' u8 B: w- a! |6 Cif not balance take the heavy and then
% g0 c% |1 }2 J3 i& Y4 o公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it
. a5 r2 k: r, u! d! W: ?5 a" d公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
& K" E1 s( c8 m  U/ S" ptvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇2 e# `8 A1 p5 t/ {6 P
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me