zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次; X0 T" I9 l' t, H  J1 e
将比较重的那份再平均分成两份成一次2 u/ a8 R7 a" Y7 ^+ W0 j) P
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
4 F3 S8 n/ G$ Mif  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb0 ]: m+ h0 {2 G* Z
    then goto 2 - compare rest of(4)  - 2 with 2   p$ q$ A/ v+ w& `' P
           if (left side is more weight)
2 Q+ n' \# |; p, A  b              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇( f& i( K1 \& F. u% p4 e# u
          else ( right side is more weight)
9 `+ {6 h5 t0 L4 b2 \" F  e* Ytvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
, F: q) v6 z/ M+ L# yelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。