zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次tvb now,tvbnow,bttvb) C/ c8 K4 _: ?1 \& Y4 ]9 {
将比较重的那份再平均分成两份成一次
% r/ c1 z1 W/ w# X! ttvb now,tvbnow,bttvb剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
/ W8 U7 S4 Q& H! ^- Q% V$ B" zif  (4v4)= same that means the rest of 4 is got more weight
% [% y( b2 M( Y+ u    then goto 2 - compare rest of(4)  - 2 with 2 . ^6 D" n9 c  n: c1 s
           if (left side is more weight)
5 g1 B$ M, E* W9 T) utvb now,tvbnow,bttvb              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answerwww.tvboxnow.com$ w! M# W$ ^* Z& N: x* Q3 S
          else ( right side is more weight)
- }1 i4 ]# c$ f1 X2 e2 O              then goto 3 - compare last (right side of (2) - 1 with 1 => get answerwww.tvboxnow.com! b" B4 O1 D8 D9 R5 G' N
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。