1 - compare 4 with 4
: i0 [7 {1 u# h2 |9 L& Htvb now,tvbnow,bttvbif (4v4)= same that means the rest of 4 is got more weight
, _! o7 b7 S0 z9 T) nTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 then goto 2 - compare rest of(4) - 2 with 2
. Y8 s% |+ d! z7 q if (left side is more weight)
" z- v) E- T8 z6 D3 h' UTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
4 f. Q- H0 F* n/ @/ g( x; D& k6 g% {www.tvboxnow.com else ( right side is more weight)8 W1 o5 N7 [& z S' E2 f/ c2 X9 H
then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
$ P+ n% o3 t& O4 y, k$ J9 htvb now,tvbnow,bttvbelse ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
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