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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
2 w# g8 K$ \/ h" ~+ lwww.tvboxnow.com将比较重的那份再平均分成两份成一次- ?  _* }' t6 L% E, X# u0 I0 j
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
1 O: r$ j( O; \6 D3 Etvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight
" e5 l% u5 B0 a. ?0 D( `# J( A公仔箱論壇    then goto 2 - compare rest of(4)  - 2 with 2
" d: {  |! @: L0 Z) t. h           if (left side is more weight)www.tvboxnow.com: m, D/ O  E( b+ G( j9 e. q
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer) Q: x  N5 ~$ L
          else ( right side is more weight)公仔箱論壇4 a, j! J+ o7 B6 z% k7 _
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb! V4 m- ]: R) F  y4 E/ }
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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