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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆6 z8 N; |2 y3 H6 P: w% r
共四堆
/ I# H# T5 c( ~0 N称两次得出异常的在那一堆,其轻重
1 u3 @, X1 q8 X6 _在异常的那一堆中在称一次# G) L: F, c% t7 W
就可以找到了
divde the 12 balls into 3 sets of 4.
& A. q7 P/ I7 U8 l  K$ \tvb now,tvbnow,bttvbweight any 2 sets.tvb now,tvbnow,bttvb3 F+ g; Z7 R/ Y" o' [6 h
if the 2 sets are equal, then you know the heavy one is in the third
. f7 d8 }) J. Q8 {/ R' `tvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set
5 r& }) M5 Q; f, a6 ]' H  N- R公仔箱論壇then divide the 4 balls into 2.
1 i( w. i3 d3 `weigh them
+ ?& K0 f! D9 R4 Y* cand divide the heavier into 1
- g. ]# `7 j5 p3 n+ w  g7 K, _tvb now,tvbnow,bttvband weight them.
" ?2 J' J/ m4 |" m' o; Htvb now,tvbnow,bttvb3 x weighing and get the ans.  
, }+ N" C$ G, g# m( \# t8 R+ m% qwww.tvboxnow.comin less than 15 secs.
1. 6 aside and weight.
2 Z/ n- S* f) J; l9 u/ T- btvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.* c. \, ~- Q6 L7 g2 u) W, {& m
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 公仔箱論壇' w9 E  e$ G9 I! J  n% \; ^, @
tvb now,tvbnow,bttvb( e7 f0 E, E% @/ }
but i have a question. 重量異常 can be heavier or lighter.... so......
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