put six on each side first3 x8 L8 `( d* ]3 y8 l8 a9 I! C8 e, U
tvb now,tvbnow,bttvb; n& K. m. h6 C. W3 d, W; o
from the heavier six, split it to three on each side
$ x/ Z" ]& b2 r" m, l) Y. ptvb now,tvbnow,bttvbtvb now,tvbnow,bttvb& [/ J) u: w/ x) a: ^
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |